2.2.1 Koormusvektor takistatud väändel

Koormusvektori $\mathrm{\mathbf{\stackrel{\rm\circ}{Z}}}$ esitame kujul

$$\mathbf{\stackrel{\rm\circ}{Z}} = \left[\begin{array}{c} \theta_{... ... \\ E\hspace*{1pt}I_{\omega}\theta^{\prime\prime\prime}_{e} \end{array}\right]$$ (2.77)

Koormusvektori leidmist alustame erilahendist (2.51):

$$\theta_{e} = {\theta}_{4\hspace*{1pt}e}\left(x\right) = \hspace*{1pt}\frac{m_{... ...{1pt}\kappa^{2}\hspace*{1pt} \frac{\left(x - a\right)^{2}_{+}}{2} \right] \quad$$ (2.78)

$$T_{t\hspace*{1pt}e} = {GI_{t}}{\theta}^{\prime}_{4\hspace*{1pt}e}\left(x\right) = \hspa... ...ace*{1pt}} - \hspace*{1pt}{{\kappa\left(x - a\right)_{+}}\hspace*{1pt}} \right]$$ (2.79)

$$B_{\omega\hspace*{1pt}e} = -{GI_{t}}\frac{1}{\kappa^{2}}{\theta}^{\prime\prime}_{4\hspace*{1... ...}\mathrm{ch}\hspace*{1pt} {{\kappa\left(x - a\right)_{+}}\hspace*{1pt}} \right]$$ (2.80)

$${T_{\omega\hspace*{1pt}e}} = -{GI_{t}}\frac{1}{\kappa^{2}}{\theta}^{\prime\prime\prime}_{4\hsp... ... \mathrm{sh}\hspace*{1pt} {{\kappa\left(x - a\right)_{+}}\hspace*{1pt}} \right]$$ (2.81)

Avaldistest (2.78)-(2.81) moodustame lausmomendi $m_{x}$ koormusvektori

$$\mathbf{\stackrel{\rm\circ}{Z}} = \left[\begin{array}{c} \theta_{... ...{1pt} {{\kappa\left(x - a\right)_{+}}\hspace*{1pt}} \right]} \end{array}\right]$$ (2.82)